v3 problem - please help

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mattjwright
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v3 problem - please help

Post by mattjwright »

Hi - I hope you can help me.

I'm trying to update the navigation on a charity website - they are currently un-able to update to the new version..
I'm having problems spawning extra dropdown areas using the showmenu feature.

ie

"why us","show-menu8",,,1,


The site currently uses 9 showmenu sub navigation links, they now want around 20 in total.
But for example when I try to create a new sub nav using say showmenu number 15
ie
"why us","show-menu15",,,1,

And then add the new sub menu code, it doesn't work and throws a wobbler.

Even swapping previous ones which work and renaming them in a higher number creates this problem.

Can you only create a certain number of dropdowns and sub dropdowns ??

I'm really confused and hope someone has some ideas.

Many thanks
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Ruth
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Post by Ruth »

I did discover when I was using version3 as version5 was in development that after a certain amount of menus nothing would work. The page would load and start working but on mouseover everything would freeze. I think it is just too much for the menu.

Could you explain why the charity site can't update? There may be some solution for that, version 5 is so much better, works so much better and has so many more features, though you are not required to use them :)
And there is a conversion tool which converts the old menu_array.js file and doesn't need too much fixing, i.e. removing some extra semi-colons, deleting the Effect from the top and putting the code into the overfilter section, is about all that needs doing.

Ruth
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kevin3442
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Post by kevin3442 »

Hi Matt,

I think Ruth's question about updating also speaks to the fact that a charity site could probably qualify for a free license.

Regarding use of v3. I think the problem may be that you simply aren't using the correct syntax (unless there's a really old release of v3 that I haven't seen that uses a different syntax). Your example:

Code: Select all

"why us","show-menu8",,,1, 
implies that you have a submenu named "menu8". To use show-menu to open a menu named "menu8", you would use:

Code: Select all

"why us","show-menu=menu8",,,1, 
In other words, the correct syntax for show-menu is "show-menu=menuName", with an equals sign between the show-menu property and the name of the menu to show.

Kevin
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